2X^2-4x-600=0

Solution for 2X^2-4x-600=0 equation:

2X^2-4X-600=0

a = 2; b = -4; c = -600;
Δ = b2-4ac
Δ = -42-4·2·(-600)
Δ = 4816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4816}=\sqrt{16*301}=\sqrt{16}*\sqrt{301}=4\sqrt{301}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{301}}{2*2}=\frac{4-4\sqrt{301}}{4}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{301}}{2*2}=\frac{4+4\sqrt{301}}{4}
$